[RFC][Info] Playing with Boom-Boom (Or, Antimatter and You - A Children's Parable)

[Labster]

There's a lot of extraneous information here.  The relevant equation here is E = m₀c², where m₀ is the rest mass and c is the speed of light.  Of course, not all of the mass will be lost, because you're going to produce some electron/positron pairs and neutrinos in addition to all the light.  But those are three orders of magnitude or more less massive, so we can safely ignore them for our purposes -- we're not writing physics papers.  Some will be lost to kinetic energy of neutrinos, most of which can pass through an entire planet without reacting with anything -- but they're so light-massed we're going to ignore that too.  Everything else counts as explosive power.

c² = (2.998×10⁸)² = 89880040000000000 = 8.988×10¹⁶ m²/s²

This is... a pretty big factor.  When you multiply that with kilograms, you get joules.  So for 1 gram of antimatter reacting with 1 gram of matter:

10⁻³ kg × 2 × 8.988×10¹⁶ m²/s²  = 1.7976×10¹⁴ J = 0.18 PJ

So yeah, the math is fine, but why is he screwing around with moles?  This guy sounds like a chemist pretending to do physics.

Keep in mind, usage has effects on the quantity of the availability of neutral matter.

Even at the Kármán line, you have ~10mg/m³ of matter around.  And remember, you can always use your own blood as a matter source.